How do you determine if $5y+3x=1$ is parallel, perpendicular to neither to the line $y+10x=-3$ ?

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Answer 1 · 2014-11-05T17:04:51

Let us rewrite them in Slope-Intercept Form, which essentially means that we solve for $y$ .

Line 1: $5y+3x=1$

by subtracting $3x$ ,

$=> 5y=-3x+1$

by dividing by $5$ ,

$=> y=-3/5x+1/5$

So, the slope is $m_1=-3/5$ .

Line 2: $y+10x=-3$

by subtracting $10x$ ,

$=>y=-10x-3$

So, the slope is $m_2=-10$ .

Since $m_1 ne m_2$ , they are not parallel.

Since $m_1 cdot m_2 ne -1$ , they are not perpendicular.

Hence, they are neither.

I hope that this was helpful.

How do you determine if 5y+3x=1 5y+3x=1 is parallel, perpendicular to neither to the line y+10x=-3y+10x=-3?