What is the derivative of # y = x [sec (3 - 8x)]#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Martin C. Mar 18, 2018 #1/cos(3-8x)(1-8xtan(3-8x))# Explanation: #y = x [sec (3 - 8x)]=x/cos(3-8x)# #y'=1/cos(3-8x)-8*sin(3-8x)*x/(cos(3-8x)^2)# #=1/cos(3-8x)(1-8xtan(3-8x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2131 views around the world You can reuse this answer Creative Commons License