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What is the derivative of # y= ln(2x)/x^2#?

1 Answer

Apr 16, 2017

#dy/dx=(1-2ln(2x))/x^2#

Explanation:

Use quotient rule and chain rule :

#dy/dx=(2(1/(2x))(x^2)-(ln(2x)(2x)))/x^4#

Simplify:

#dy/dx=(x-ln(2x)(2x))/x^4#

Take out a #x# from the numerator and denominator:

#dy/dx=(1-2ln(2x))/x^2#

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