What is the derivative of # y=e^((2x)/3)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Jim H Aug 20, 2015 #y' = 2/3 e^((2x)/3)# Explanation: #d/dx(e^u) = e^u (du)/dx# #" "" "# (Chain rule) In this case # u = (2x)/3# so #(du)/dx = 2/3# #d/dx(e^((2x)/3)) = e^((2x)/3) * 2/3 = 2/3 e^((2x)/3)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1386 views around the world You can reuse this answer Creative Commons License