What is the derivative of $f(x)=ln(x^2+x)$ ?

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Answer 1 · 2014-09-24T16:46:13

We find the derivative by using the chain rule.

$f(x)=ln(x^2+x)$

$f'(x)=1/(x^2+x)*(x^2+x)'$

$f'(x)=1/(x^2+x)*(2x+1)$

$f'(x)=(2x+1)/(x^2+x)$

What is the derivative of f(x)=ln(x^2+x)f(x)=ln(x^2+x) ?