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What is the derivative of #y = 10^(1-x^2)#?

1 Answer

Jun 21, 2016

# y' = -2\ln (10) \ x \ 10^{1-x^2} # x

Explanation:

take natural logs

#\ln y = \ln (10^(1- x^2)) = (1- x^2) \ln (10) #

#\\frac{1}{y} y' = - 2x \ln( 10) #

# y' = - 2x \ln 10 \times y = -2\ln (10) \ x \ 10^{1-x^2} #

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