What is the derivative of #x^(2/3)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Guilherme N. Jun 4, 2015 This is a simply appliance of power rule, which states Be #y=a^n#, then #(dy)/(dx)=n*a^(n-1)# Thus, #(dy)/(dx)=x^(3/2-1)=x^(1/2)=sqrt(x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 9737 views around the world You can reuse this answer Creative Commons License