What is the derivative of this function #sin(x+1)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer marfre Mar 1, 2017 #f(x)' = cos(x+1)# Explanation: Use the chain rule: #(sin u)' = (cos u)u'# Let #u = x + 1#, so #u' = 1# #f(x)' = (cos(x+1))(1) = cos(x+1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1008 views around the world You can reuse this answer Creative Commons License