# What is the derivative of sqrtx^3?

Jun 22, 2015

You can rewrite the function as ${x}^{\frac{3}{2}}$

#### Explanation:

Then you move the exponent to the front, and lower it by 1:

$f ' \left(x\right) = \frac{3}{2} \cdot {x}^{\left(\frac{3}{2} - 1\right)} = \frac{3}{2} \cdot {x}^{\frac{1}{2}} = \frac{3}{2} \sqrt{x}$