# What is the derivative of (sqrt 6)/x^5 using the Power Rule?

$f \left(x\right) = {x}^{- 5} \sqrt{6}$
now derive as ${x}^{n}$ giving $n {x}^{n - 1}$
to get: $f ' \left(x\right) = - 5 {x}^{- 6} \sqrt{6} = - 5 \frac{\sqrt{6}}{x} ^ 6$
where $\sqrt{6}$ is a constant.