What is the derivative of #sqrt(2x+3)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer ali ergin · Jim H Mar 7, 2016 #d/(d x)sqrt (2x+3)=2/(2sqrt (2x+3)) = 1/sqrt(2x+3)# Explanation: #d/(d x)sqrt u=(d/(d x )u)/(2sqrt u)# #d/(d x)sqrt (2x+3)=2/(2sqrt( 2x+3)) = 1/sqrt(2x+3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1235 views around the world You can reuse this answer Creative Commons License
