# What is the derivative of sin(x^2 -2)^3?

$\frac{d}{\mathrm{dx}} \sin {\left({x}^{2} - 2\right)}^{3} = 6 x {\left({x}^{2} - 2\right)}^{2} \cos {\left({x}^{2} - 2\right)}^{3}$.
$\frac{d}{\mathrm{dx}} \sin {\left({x}^{2} - 2\right)}^{3} = \cos {\left({x}^{2} - 2\right)}^{3} \cdot 3 {\left({x}^{2} - 2\right)}^{2} \cdot 2 x$
$= 6 x {\left({x}^{2} - 2\right)}^{2} \cos {\left({x}^{2} - 2\right)}^{3}$.