What is the derivative of # sin (x/2)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Euan S. Aug 1, 2016 #1/2cos(x/2)# Explanation: We use the chain rule, as we have #y(u(x))# #(dy)/(dx) = (dy)/(du)(du)/(dx)# #u = x/2 implies (du)/(dx) = 1/2# #y = sin(u) implies (dy)/(du) = cos(u)# #therefore (dy)/(dx) = cos(u)*1/2 = 1/2cos(x/2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1003 views around the world You can reuse this answer Creative Commons License