What is the derivative of #sec^2(x)*tan^2(x)#? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer bp Feb 26, 2017 #2tan x sec^4 x +2sec^2 x tan^3 x# Explanation: Using product rule, the derivative would be #sec^2 x d/dx (tan^2 x) +tan^2 x d/dx (sec^2 x)# =#sec^2 x (2 tan x sec^2 x) + tan^2 x (2 secx secx tan x)# =#2tan x sec^4 x +2sec^2 x tan^3 x# Answer link Related questions What is Derivatives of #y=sec(x)# ? What is the Derivative of #y=sec(x^2)#? What is the Derivative of #y=x sec(kx)#? What is the Derivative of #y=sec ^ 2(x)#? What is the derivative of #y=4 sec ^2(x)#? What is the derivative of #y=ln(sec(x)+tan(x))#? What is the derivative of #y=sec^2(x)#? What is the derivative of #y=sec^2(x) + tan^2(x)#? What is the derivative of #y=sec^3(x)#? What is the derivative of #y=sec(x) tan(x)#? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 1846 views around the world You can reuse this answer Creative Commons License