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What is the derivative of #y=sec^2(x)#?

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Sep 21, 2014

We need to use the chain rule

#y=sec^2(x)#

Let #u=sec(x)#

#u'=sec(x)tan(x)#

#y=u^2#

#y'=2u*u'#

#y'=2sec(x)* sec(x)tan(x)=2sec^2(x)tan(x)#

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