What is the derivative of $Sec^2 pi(x)$ ?

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Answer 1 · 2017-06-07T15:05:30

$dy/dx = 2pisec^2pixtanpix$

Use the chain rule to differentiate $y=sec^2pix$

Let $u=secpix$ and $y=u^2$

$dy/(du) = 2u=2secpix$

$(du)/dx= pisecpixtanpix$

Chain rule:

$dy/dx=dy/(du) xx (du)/dx$

$dy/dx = 2secpix xx pisecpixtanpix = 2pisec^2pixtanpix$

What is the derivative of Sec^2 pi(x) Sec^2 pi(x) ?