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What is the derivative of #sec^-1(x^2)#?

1 Answer

Aug 24, 2016

#y=sec^-1x^2 rArr dy/dx=2/(|x|sqrt(x^4-1)#.

Explanation:

Let #y=sec^-1x^2#

#:. dy/dx=1/(|x^2|sqrt(x^4-1))*d/dx(x^2)#.

#=(2x)/(|x^2|sqrt(x^4-1))#.

#:. dy/dx=2/(|x|sqrt(x^4-1)#.

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