What is the derivative of # ln(e^(4x)+3x)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Anish M. · David B. Apr 5, 2018 #d/(dx) ln(e^(4x)+3x)=(4e^(4x)+3)/(e^(4x)+3x)# Explanation: Derivative of #lnx# is #1/x# So derivative of #ln(e^(4x)+3x)# is #1/(e^(4x)+3x)d/dx(e^(4x)+3x)# (Chain rule) Derivative of #e^(4x)+3x# is #4e^(4x)+3# So derivative of #ln(e^(4x)+3x)# is #1/(e^(4x)+3x)*(4e^(4x)+3)# #=(4e^(4x)+3)/(e^(4x)+3x)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1835 views around the world You can reuse this answer Creative Commons License