What is the derivative of #ln(6x)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Jim H Sep 28, 2015 #d/dx(ln(6x)) = 1/x# Explanation: #ln(6x) = ln6 + lnx# #ln6# is a constant, so its derivative is #0#. #d/dx(ln(6x)) = d/dx(ln6) + d/dx(lnx) = 0+1/x = 1/x# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 38518 views around the world You can reuse this answer Creative Commons License