Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

What is the derivative of #g(x)= x^2*sqrt(1-x^2)#?

1 Answer

Apr 14, 2015

The answer is: #y'=(2x-3x^3)/sqrt(1-x^2)#.

For the product rule:

#y'=2x*sqrt(1-x^2)+x^2*1/(2sqrt(1-x^2))*(-2x)=#

#=2x*sqrt(1-x^2)-x^3/sqrt(1-x^2)=(2x(1-x^2)-x^3)/sqrt(1-x^2)=#

#=(2x-3x^3)/sqrt(1-x^2)#.

Related questions

See all questions in Chain Rule

Impact of this question

1637 views around the world

You can reuse this answer
Creative Commons License