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What is the derivative of #g(x)=-3 root3 (2-9x) #?

1 Answer

Mar 1, 2016

#g'(x)=9(2-9x)^(-2/3)#

Explanation:

#g(x)=-3(2-9x)^(1/3)#

Applying the chain rule#rArr#

#g'(x)=-3[1/cancel(3)(2-9x)^(-2/3)xx-cancel(9)3]#

#:.g'(x)=-3[-3(2-9x)^(-2/3)]#

#:.g'(x)=9(2-9x)^(-2/3)#

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