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What is the derivative of #f(x)= xln(x^3-4)#?

1 Answer

Dec 4, 2016

#f'(x)= (3x^3)/(x^3-4) + ln(x^3-4)#

Explanation:

#f(x) = xln(x^3-4)#

#f'(x) = x*d/dx ln(x^3-4) + ln(x^3-4)*1# [Product Rule]

#= x* 1/(x^3-4) * (3x^2) + ln(x^3-4)# [Standard differential and Chain Rule]

#= (3x^3)/(x^3-4) + ln(x^3-4)#

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