What is the derivative of #f(x)=sin(lnx)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Bill K. Nov 11, 2015 #f'(x)=cos(ln(x)) * 1/x# Explanation: Use the facts that #d/dx(sin(x))=cos(x)#, #d/dx(ln(x))=1/x#, and the Chain Rule: #d/dx(f(g(x)))=f'(g(x)) * g'(x)# with #f(x)=sin(x)# and #g(x)=ln(x)#. Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 39328 views around the world You can reuse this answer Creative Commons License