What is the derivative of #f(x) = sin (cos (tanx) )#? Calculus Basic Differentiation Rules Chain Rule 1 Answer 1s2s2p Mar 13, 2018 #f'(x)=-sec^2xsin(tanx)cos(cos(tanx))# Explanation: #f(x)=sin(g(x))# #f'(x)=g'(x)cos(g(x))# #g(x)=cos(h(x))# #g'(x)=-h'(x)sin(h(x))# #h(x)=tan(x)# #h'(x)=sec^2x# #g'(x)=-sec^2xsin(tanx)# #g(x)=cos(tanx)# #f'(x)=-sec^2xsin(tanx)cos(cos(tanx))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 7566 views around the world You can reuse this answer Creative Commons License