# What is the derivative of #f(x)= ln2x#?

##### 1 Answer

Jan 15, 2016

#### Explanation:

According to the chain rule,

#d/dx[lnu]=1/u*u'#

Thus,

#d/dx[ln2x]=1/(2x)*d/dx[2x]#

#=1/(2x)*2=1/x#

Another way to think about this problem is to first split up the logarithm using logarithm rules:

#f(x)=ln2+lnx#

Thus, when differentiating,

#f'(x)=d/dx[lnx]=1/x#