What is the derivative of #f(x)=ln (x^2+2)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Shwetank Mauria May 12, 2016 #(df)/dx=(2x)/(x^2+2)# Explanation: Derivative of #f(x)=ln(x^2+2)# can be found using chain formula, as #f(x)=ln(g(x))# and #g(x)=(x^2+2)# Hence, #(df)/dx=1/(x^2+2)xx2x=(2x)/(x^2+2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 972 views around the world You can reuse this answer Creative Commons License