What is the derivative of #cos( sin( x ))#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Henry W. Oct 20, 2016 #(dy)/(dx)=-sin(sin(x))cos(x)# Explanation: #d/(dx)cos(sin(x))# Using chain rule, #(dy)/(dx)=(dy)/(du)*(du)/(dx)#, let #u=sin(x)# #(dy)/(du)=d/(du)cosu=-sinu=-sin(sin(x))# #(du)/(dx)=d/(dx)sin(x)=cos(x)# #:.(dy)/(dx)=-sin(sin(x))*cos(x)=-sin(sin(x))cos(x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 37685 views around the world You can reuse this answer Creative Commons License