What is the derivative of cos[sin−1(2w)]? Calculus Basic Differentiation Rules Chain Rule 1 Answer Monzur R. Feb 12, 2017 dydw=−4w√1−4w2 Explanation: Let y=cos(sin−1(2w)) Let u=sin−1(2w) sinu=2w dudwcosu=2 dudw=2cosu cos2u+sin2u=1 cos2u=1−sin2u=1−(2w)2 cosu=√1−4w2 dudw=2√1−4w2 ddwcos(u)=−sin(u)×dudw =−sin(sin−1(2w))×2√1−4w2 =−4w√1−4w2 Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y=6cos(x2) ? How do you find the derivative of y=6cos(x3+3) ? How do you find the derivative of y=ex2 ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(ex+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y=(4x−x2)10 ? How do you find the derivative of y=(x2+3x+5)14 ? How do you find the derivative of y=(1+x1−x)3 ? See all questions in Chain Rule Impact of this question 3340 views around the world You can reuse this answer Creative Commons License