What is the derivative of cos[sin1(2w)]?

1 Answer
Feb 12, 2017

dydw=4w14w2

Explanation:

Let y=cos(sin1(2w))

Let u=sin1(2w)

sinu=2w

dudwcosu=2

dudw=2cosu

cos2u+sin2u=1

cos2u=1sin2u=1(2w)2

cosu=14w2

dudw=214w2

ddwcos(u)=sin(u)×dudw

=sin(sin1(2w))×214w2

=4w14w2