# What is the derivative of (2x-1)^3?

Feb 22, 2016

$f ' \left(x\right) = 6 {\left(2 x - 1\right)}^{2}$

#### Explanation:

The derivative of this function involved the power and chain rule, and here is the formula for it

let $f \left(x\right) = {g}^{n} ^ n$ , then f'(x) = ng]^(n-1) (g')

Given $f \left(x\right) = {\left(2 x - 1\right)}^{3}$

$n = 3$ , $g \left(x\right) = 2 x - 1$ , $g ' \left(x\right) = 2$

$f ' \left(x\right) = 3 {\left(2 x - 1\right)}^{2} \left(2\right)$

$= 6 {\left(2 x - 1\right)}^{2}$