What is f(x) = int x-x^2secx dx if f(pi/4)=3 ?

1 Answer
Aug 13, 2018

int(x-x^2)dx=x^2/2-x^3/3+3+pi^3/192-pi^2/32 if f(pi/4)=3

Explanation:

I=int(x-x^2)dx

=intxdx-intx^2dx

=x^2/2-x^3/3+C, C in RR

Also, f(pi/4)=3

(pi/4)^2/2-(pi/4)^3/3+C=3

C=3+pi^3/192-pi^2/32

Finally, I=x^2/2-x^3/3+3+pi^3/192-pi^2/32

\0/ here's our answer !