What is f(x) = int x-x^2secx dx if f(pi/4)=3 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Guillaume L. Aug 13, 2018 int(x-x^2)dx=x^2/2-x^3/3+3+pi^3/192-pi^2/32 if f(pi/4)=3 Explanation: I=int(x-x^2)dx =intxdx-intx^2dx =x^2/2-x^3/3+C, C in RR Also, f(pi/4)=3 (pi/4)^2/2-(pi/4)^3/3+C=3 C=3+pi^3/192-pi^2/32 Finally, I=x^2/2-x^3/3+3+pi^3/192-pi^2/32 \0/ here's our answer ! Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1765 views around the world You can reuse this answer Creative Commons License