What is #f(x) = int 1/(x^2+3) # if #f(2)=1 #?

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What is #f(x) = int 1/(x^2+3) # if #f(2)=1 #?

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Answer 1 · 2016-03-16T16:06:41

#f(x)=int1/(x^2+3) = 1/sqrt3 tan^-1(x/sqrt3) +C#
#f(2)=1/sqrt3 tan^-1(2/sqrt3) +C=1#
#C=1-(1/sqrt3 tan^-1(2/sqrt3))~~0.505#
#f(x)=int1/(x^2+3) = 1/sqrt3 tan^-1(x/sqrt3) +0.505#

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What is #f(x) = int 1/(x^2+3) # if #f(2)=1 #?

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