What is F(x) = int x-e^(-x) dx if F(0) = 2 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Mia Sep 15, 2016 F(x)=x^2/2+e^(-x)+1 Explanation: F(x)=intx-e^(-x)dx F(x)=x^2/2+e^(-x)+C where C is a constant number Let's find C given F(0)=2 F(0)=2 (0)^2/2+e^(-0)+C=2 0+1+C=2 C=2-1 C=1 Therefore, F(x)=x^2/2+e^(-x)+1 Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1290 views around the world You can reuse this answer Creative Commons License