What is f(x) = int x-e^(x-3)dx if f(0)=-2 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Sonnhard Jul 12, 2018 f(x)=x^2/2-e^(x-3)-2-e^(-3) Explanation: using that int x-e^(x-3) dx=x^2/2-e^(x-3)+C we get that f(0)=e^(-3)+C=-2 so C=-2-e^(-3) we have used that int xdx=x^2/2+C_1 int e^(x-3)dx=e^(x-2)+C_2 Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1330 views around the world You can reuse this answer Creative Commons License