What is f(x) = int x-3e^x dx if f(1) = 0 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Will Sep 12, 2016 C = 3e-1/2 Explanation: First intx -3e^x dx = intx dx - 3inte^x dx so 1/2x^2 - 3e^x+C if f(1)=0 1/2 - 3e+C = 0 C = 3e-1/2 Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1642 views around the world You can reuse this answer Creative Commons License