What is f(x) = int x^3-x+xe^x dx if f(1) = 3 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Monzur R. May 1, 2017 f(x)=1/4x^4-1/2x^2+xe^x-e^x+11/4 Explanation: f(x)=intx^3-x+xe^x dx Integrate each term separately: f(x)=1/4x^4-1/2x^2+xe^x-e^x+"c" f(1)=1/4(1)^4-1/2(1)^2+1e^1-e^1+"c"=3 "c"=11/4 f(x)=1/4x^4-1/2x^2+xe^x-e^x+11/4 Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1325 views around the world You can reuse this answer Creative Commons License