What is f(x) = int x^3-2x dx if f(-2)=-1 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Trevor Ryan. Apr 9, 2016 f(x)=int(x^3-2x)dx =x^4/4-(2x^2)/2+C Now applying the initial boundary condition we get f(-2)=-1=>C=-1 therefore f(x)=1/4x^4-x^2-1 Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1541 views around the world You can reuse this answer Creative Commons License