What is f(x) = int (x+3)^2-x dx if f(-1) = 0 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Leland Adriano Alejandro Jan 15, 2016 f(x) = x^3/3+(5x^2)/2+9x+41/6 Explanation: after integration f(x)=x^3/3+(5x^2)/2+9x+C 0=(-1)^3/3+(5(-1)^2)/2+9(-1)+C C=41/6 Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1268 views around the world You can reuse this answer Creative Commons License