What is f(x) = int (x+3)^2-2x dx if f(1) = 0 ?

1 Answer
Dec 19, 2017

f(x)=1/3(x+3)^3-x^2-61/3

Explanation:

f(x)=int(x+3)^2-2xdx

Use inth(x)+g(x)dx=inth(x)dx+intg(x)dx
f(x)=int(x+3)^2dx-int2xdx
f(x)=1/3(x+3)^3-x^2+C

Evaluate the constant of integration
0=1/3(1+3)^3-1^2+C
0=1/3(4)^3-1+C
0=64/3-3/3+C
0=61/3+C
C=-61/3