What is f(x) = int (x^2-2x)(e^x-sinx) dx if f(1 ) = 2 ?
1 Answer
Mar 15, 2016
Explanation:
Using the rule
u=x^2-2x =>du=(2x-2)dx
dv=(e^x-sinx)dx =>v=e^x+cosx
Once again using the rule above mentioned:
u=2x-2 =>du=2dx
dv=(e^x+cosx)dx =>v=e^x+sinx
Finding
f(1)=2
1(e+cos1)-2(cancel(2e)+cancel(sin1)+cos1)+cancel(4e)+cancel(2sin1)-2cos1+const.=2
e-3cos1+const.=2 =>const.=2-e+3cos1~=0.903
So