What is #f(x) = int -sinx dx# if #f(pi/3) = -6 #?

1 Answer
Jim G.
Oct 29, 2016

#cosx-13/2#

Explanation:

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(intsinx dx=-cosx)color(white)(2/2)|)))#

#rArrint-sinxdx=cosx+c#

where c is the constant of integration.

We find c, using #f(pi/3)=-6#

#rArrcos(pi/3)+c=-6#

#rArr1/2+c=-6rArrc=-13/2#

#rArrF(x)=cosx-13/2#

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