What is f(x) = int -sinx dx if f(pi/3) = -6 ?

1 Answer
Oct 29, 2016

cosx-13/2

Explanation:

color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(intsinx dx=-cosx)color(white)(2/2)|)))

rArrint-sinxdx=cosx+c

where c is the constant of integration.

We find c, using f(pi/3)=-6

rArrcos(pi/3)+c=-6

rArr1/2+c=-6rArrc=-13/2

rArrF(x)=cosx-13/2