What is f(x) = int -sinx dx if f(pi/3) = -6 ?
1 Answer
Oct 29, 2016
Explanation:
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rArrint-sinxdx=cosx+c where c is the constant of integration.
We find c, using
f(pi/3)=-6
rArrcos(pi/3)+c=-6
rArr1/2+c=-6rArrc=-13/2
rArrF(x)=cosx-13/2