What is F(x) = int sin(3x)-sinxcos^2(4x) dx if F(pi) = 3 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Monzur R. Apr 28, 2017 F(x) =1/2cosx-1/3cos3x-1/28cos7x+1/36cos9x+199/63 Explanation: F(x) = int sin3x - sinxcos^2(4x)dx= 1/2cosx-1/3cos3x-1/28cos7x+1/36cos9x+"c" F(pi)= -10/63 + "c"=3 "c"=199/63 F(x) =1/2cosx-1/3cos3x-1/28cos7x+1/36cos9x+199/63 Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1244 views around the world You can reuse this answer Creative Commons License