What is F(x) = int sin(3x)-sinxcos^2(4x) dx if F(pi) = 3 ?

1 Answer
Apr 28, 2017

F(x) =1/2cosx-1/3cos3x-1/28cos7x+1/36cos9x+199/63

Explanation:

F(x) = int sin3x - sinxcos^2(4x)dx=
1/2cosx-1/3cos3x-1/28cos7x+1/36cos9x+"c"

F(pi)= -10/63 + "c"=3

"c"=199/63

F(x) =1/2cosx-1/3cos3x-1/28cos7x+1/36cos9x+199/63