What is f(x) = int sec^2x- cosx dx if f((5pi)/4) = 0 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer sjc Dec 11, 2016 f(x)=tanx-sinx-(1+sqrt2/2) Explanation: int(sec^2x-cosx)dx f(x)=tanx-sinx+c f((5pi)/4)=tan((5pi)/4)-sin((5pi)/4)+c=0 1-(-sqrt2/2)+c=0 c=-(1+sqrt2/2) f(x)=tanx-sinx-(1+sqrt2/2) Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1319 views around the world You can reuse this answer Creative Commons License