What is f(x) = int e^(2x)-e^x+x^2 dx if f(1) = 0 ?
1 Answer
Jul 10, 2017
Zero.
Explanation:
First integrate:
f(x)=inte^(2x)-e^x+x^2dx
=1/2e^(2x)-e^x+1/3x^3+C
So, for
0=1/2e^2-e+1/3+C
Then you can solve for C.
C=-e^2/2+e-1/3
So,
f(x)=inte^(2x)-e^x+x^2dx=1/2e^2-e+1/3+(-e^2/2+e-1/3)
=0