What are the first and second derivatives of #f(x)=e^(2x)(lnx) #?

Question

2858 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-08T13:04:48

#f^'(x)= e^(2x)( 1/x+ 2(lnx))#
#f^''(x)= (e^(2x)(2x-1))/ x^2#
#+ 2 e^(2x) ( 1/x+ 2 *(lnx))#

#f(x)= e^(2x)(ln x)#

#f^'(x)= e^(2x)* 1/x+ 2e^(2x)*(lnx)#

#f^'(x)= e^(2x)( 1/x+ 2(lnx))#

#f^''(x)= (x *2e^(2x)-e^(2x)*1)/ x^2#

#+ 2(e^(2x) * 1/x+ 2e^(2x) *(lnx))#

#f^''(x)= (e^(2x)(2x-1))/ x^2#

#+ 2 e^(2x) ( 1/x+ 2 *(lnx))# [Ans]