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What are the E and Z isomers of pent-2-ene?

1 Answer

Apr 10, 2016

See below.

Explanation:

The formula of pent-2-ene is ${CH}_{3} {CH=CHCH}_{2} {CH}_{3}$ $"CH"_3"CH=CHCH"_2"CH"_3$ .

Each double-bonded carbon atom has an $H$ $"H"$ and a $C$ $"C"$ directly attached, so the molecule exhibits $E / Z$ $E//Z$ isomerism.

$C$ $"C"$ has higher priority than $H$ $"H"$ .

In ( $E$ $E$ )-pent-2-ene (on the left), the $C$ $"C"$ atoms are on opposite sides of the double bond.

E,Z isomers

In ( $Z$ $Z$ )-pent-2-ene (on the right), the $C$ $"C"$ atoms are on the same side of the double bond.

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