Three consecutive even integers have a sum of 48. What are the integers?

1 Answer
Oct 20, 2016

The three consecutive even numbers are 14, 16,and 18

Explanation:

Let color(red)(n_ be the smallest even integer.
Therefore the other two consecutive even integers will be: color(blue)(n+2) and color(green)(n+4)

We are told
color(white)("XXX")color(red)n+color(blue)(n+2)+color(green)(n+4)=48

rarr 3n+6=48

rarr 3n=42

rarr n=14