How do you solve #x=(y-1)/(y+1)# for y?

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Answer 1 · 2015-04-07T12:14:58

#color(red)(x=(y-1)/(y+1)#

Multiplying both sides of the equation with #y+1# will give us

#x*(y+1) = y-1 #

Using the Distributive property #a*(b+c) = a*b + a*c# on the left hand side, we get

#x*y + x = y -1#

Transposing #y# to the Left Hand Side and #x# to the Right Hand Side, we get

#xy-y = -1 - x#

#y*(x-1) = -(1+x)#

# y = (-(1+x))/(x-1)#

# y = ((1+x))/-(x-1)#

#color(green) (y = ((1+x))/(1-x)#