Suppose in a right triangle, cos(t)=3/4. How do you find: Sin(t)?

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Suppose in a right triangle, cos(t)=3/4. How do you find: Sin(t)?

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Answer 1 · 2015-10-06T12:18:08

#sin(t)=sqrt(7)/4#

Explanation:

If #cos(t)=3/4#
then a triangle with a hypotenuse of length #4#
in standard position (#/_t# at origin and adjacent side along positive X-axis)
would have an opposite side with a length of #sqrt(4^2-3^2) = sqrt(7)#
(based on Pythagorean Theorem)

#sin= ("opposite")/("hypotenuse")#

So #sin(t) = sqrt(7)/4#

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Suppose in a right triangle, cos(t)=3/4. How do you find: Sin(t)?

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