Light is travelling at a speed of 2.29*10^8 m/s through ice. What is the index of refraction of ice?

1 Answer
Sep 6, 2016

1.31

Explanation:

We know that
Refractive index of a medium n =("Velocity of light in Vacuum "c)/("Velocity of light in medium")
Inserting given value and taking c=3xx10^8ms^-1, we get

Refractive index of ice n=(3xx10^8)/(2.29xx10^8)

=>n=1.31