If #f(x)= x^2-x # and #g(x) = 3x^( 2/3 ) #, what is #f'(g(x)) #? Calculus Basic Differentiation Rules Chain Rule 1 Answer Mia Sep 16, 2016 #f'(g(x))=6x^(2/3)-1# Explanation: #f'(x)=2x-1# #f'(g(x))=2(g(x))-1# #f'(g(x))=2(3x^(2/3))-1# #f'(g(x))=6x^(2/3)-1# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1129 views around the world You can reuse this answer Creative Commons License